4x^2-0.8x+0.04=0

Solution for 4x^2-0.8x+0.04=0 equation:

4x^2-0.8x+0.04=0

a = 4; b = -0.8; c = +0.04;
Δ = b2-4ac
Δ = -0.82-4·4·0.04
Δ = 1.1102230246252E-16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.8)-\sqrt{1.1102230246252E-16}}{2*4}=\frac{0.8-\sqrt{1.1102230246252E-16}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.8)+\sqrt{1.1102230246252E-16}}{2*4}=\frac{0.8+\sqrt{1.1102230246252E-16}}{8}
$